4y^2=112

Solution for 4y^2=112 equation:

4y^2=112

We move all terms to the left:

4y^2-(112)=0

a = 4; b = 0; c = -112;
Δ = b2-4ac
Δ = 02-4·4·(-112)
Δ = 1792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1792}=\sqrt{256*7}=\sqrt{256}*\sqrt{7}=16\sqrt{7}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{7}}{2*4}=\frac{0-16\sqrt{7}}{8}
=-\frac{16\sqrt{7}}{8}
=-2\sqrt{7}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{7}}{2*4}=\frac{0+16\sqrt{7}}{8}
=\frac{16\sqrt{7}}{8}
=2\sqrt{7}
$